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Math & Conversion
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Geometric Sequence Calculator

nth term, sum of n terms & the infinite series sum

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Last updated September 6, 2026

Method: The nth term uses the exact closed form aₙ = a₁ · rⁿ⁻¹, the partial sum uses Sₙ = a₁(1 − rⁿ) / (1 − r), and the infinite sum uses S∞ = a₁ / (1 − r) whenever |r| < 1. When you supply two known terms, the ratio comes from r = (aₖ / aₘ)1/(k − m) and the first term from a₁ = aₘ / rm − 1.

Included: The nth term, the partial sum of the first n terms, the infinite sum when the series converges, the derived first term and common ratio, the percentage change per step, the product of the first n terms, the explicit and recursive rules, a term-by-term table with a running sum, and a numbered step-by-step solution.

Not included: Arithmetic, harmonic, quadratic or Fibonacci-style sequences, complex-number ratios, exact fraction output (values are decimals rounded to 6 places), and sums of series that are not geometric.

Disclaimer: This is a free educational tool for learning and for checking your own work, not academic or financial advice. The geometric sequence identities are exact; only the decimal display is rounded, and very large results switch to scientific notation.

๐Ÿ“ Enter your sequence

Geometric sequence: aโ‚™ = aโ‚ ยท rโฝโฟโปยนโพ

Try:

โœ… Term number 10

aโ‚™ = 1,536
growing without limit, r = 2
Sum of the first 10 terms
3,069
Infinite sum Sโˆž
diverges
First term aโ‚
3
Change per step
+100%

๐Ÿ“ The rule for this sequence

Explicit formula (nth term)
aโ‚™ = 3 ยท 2โฝโฟโปยนโพ
Recursive formula
aโ‚ = 3, ย  aโ‚™ = aโ‚™โ‚‹โ‚ ร— 2
Sum of the first n terms
Sโ‚™ = aโ‚ ยท (1 โˆ’ rโฟ) / (1 โˆ’ r)
Product of the first n terms
2.077602e+18
First terms
3612244896192...

This series does not converge. Because |r| = 2 is 1 or larger, the terms never shrink to zero, so there is no finite infinite sum. Only the partial sum Sโ‚™ of the first 10 terms is defined, and it equals 3,069.

๐Ÿ“‹ Term-by-term table

nTerm aโ‚™Running sum Sโ‚™
133
269
31221
42445
54893
696189
7192381
8384765
97681,533
101,5363,069

๐Ÿ“ Step-by-step solution

  1. 1. Write down what you know.
    aโ‚ = 3, ย  r = 2, ย  n = 10
  2. 2. Apply the nth term formula.
    aโ‚™ = 3 ยท 210 โˆ’ 1 = 3 ยท 512 = 1,536
  3. 3. Apply the partial sum formula.
    Sโ‚™ = 3 ยท (1 โˆ’ 1,024) / (1 โˆ’ 2) = 3,069
  4. 4. Check whether the infinite sum exists.
    |r| = 2 โ‰ฅ 1, so the infinite sum diverges (no finite value)

Results use the exact geometric sequence identities aโ‚™ = aโ‚rโฝโฟโปยนโพ, Sโ‚™ = aโ‚(1 โˆ’ rโฟ)/(1 โˆ’ r) and Sโˆž = aโ‚/(1 โˆ’ r) for |r| < 1. Values are rounded to 6 decimal places for display, and very large or very small results switch to scientific notation.

Geometric sequence calculator: the complete guide

A geometric sequence multiplies every term by the same fixed number. The nth term is aₙ = a₁ · rⁿ⁻¹ and the sum of the first n terms is Sₙ = a₁(1 − rⁿ) / (1 − r). Example: starting at 3 with a common ratio of 2, the 10th term is 1,536 and the first 10 terms add up to 3,069.

Before you start, confirm that your sequence really is geometric. Divide each term by the one before it. If every ratio is the same number, this page is the right tool. If every difference is the same instead, the sequence is arithmetic and grows in a straight line, so use the Arithmetic Sequence Calculator. If each term is the sum of the two before it, you have the Fibonacci pattern and want the Fibonacci Calculator.

How a geometric sequence works

Every geometric sequence is defined by exactly two numbers: the first term a₁ and the common ratio r. From those two values you can reach any term without listing the ones before it, because each step multiplies by r. Getting to term 2 takes one multiplication, term 3 takes two, and term n takes n − 1. That is why the exponent in the formula is n − 1 rather than n.

aₙ = a₁ × r(n − 1)   |   Sₙ = a₁ × (1 − rn) ÷ (1 − r)   |   S∞ = a₁ ÷ (1 − r)

The middle identity is the partial sum, valid for every ratio except r = 1. The right-hand identity is the infinite sum, and it is valid only when the absolute value of r is smaller than 1. When r = 1 the sequence is constant and the sum is simply n × a₁, because the partial sum formula would divide by zero.

Worked example: 3, 6, 12, 24, and so on

Take a₁ = 3, r = 2 and n = 10, the values loaded in the calculator above. First the nth term. Ten terms means nine multiplications by 2, so a₁₀ = 3 × 2⁹ = 3 × 512 = 1,536. Then the sum. Substituting into the partial sum formula gives S₁₀ = 3 × (1 − 2¹⁰) / (1 − 2) = 3 × (1 − 1,024) / (−1) = 3 × 1,023 = 3,069. Because |r| = 2 is larger than 1, there is no infinite sum: the terms keep growing and the total runs away.

The full sequence is 3, 6, 12, 24, 48, 96, 192, 384, 768, 1,536. Adding those ten numbers by hand also gives 3,069, which is exactly the point of the closed form: it replaces ten additions with one line of arithmetic. Push n to 20 and the closed form still answers instantly, giving a₂₀ = 1,572,864 and S₂₀ = 3,145,725, numbers that would take a while to reach by hand.

Term-by-term table for a₁ = 3, r = 2

Every value below comes from the two formulas above. Notice that each running sum is exactly the next term minus 3, which is minus a₁, a pattern unique to r = 2.

n Term aₙ Running sum Sₙ
133
269
31221
42445
54893
696189
7192381
8384765
97681,533
101,5363,069

Second worked example: a shrinking sequence

Now take a₁ = 100 and r = 0.5, so the sequence runs 100, 50, 25, 12.5, 6.25 and keeps halving. The 10th term is 100 × 0.5⁹ = 0.195313, and the sum of the first ten terms is 100 × (1 − 0.5¹⁰) / 0.5 = 199.804688. Because |r| = 0.5 is below 1, this series converges: no matter how many terms you add, the running total never passes S∞ = 100 / (1 − 0.5) = 200. It only gets closer. After 10 terms you are within 0.2 of the limit; after 20 terms you are within 0.0002.

That gap between the partial sum and the limit is exactly a₁rⁿ / (1 − r), which is why a ratio close to 1 converges so slowly. With r = 0.9 the same starting value of 100 has an infinite sum of 1,000, but the first ten terms only reach 651.32156, less than two thirds of the way there.

Third worked example: finding r from two terms

Homework often gives you two scattered terms instead of the first one. Suppose the 3rd term is 20 and the 7th term is 320. Between them lie 7 − 3 = 4 multiplications, so 20 × r⁴ = 320, which means r⁴ = 16 and r = 2. Step back to the start with a₁ = 20 / r² = 20 / 4 = 5. From there the sequence is 5, 10, 20, 40, 80, 160, 320, and asking for the 12th term gives a₁₂ = 5 × 2¹¹ = 10,240 with a partial sum of S₁₂ = 5 × (2¹² − 1) = 20,475. Switch the calculator to the two-term mode and it runs all of these steps for you.

How the ratio changes the outcome

The table below starts every sequence at a₁ = 100 and varies only the common ratio, showing the 10th term and the sum of the first 10 terms. It makes the split between shrinking and growing sequences obvious.

Ratio r 10th term Sum of 10 terms Behavior
0.50.1953199.8047converges to 200
0.813.4218446.3129converges to 500
0.938.742651.3216converges to 1,000
11001,000constant, diverges
1.1235.79481,593.7425grows, diverges
1.25745.05813,325.2903grows, diverges
1.53,844.335911,333.0078grows, diverges
251,200102,300doubles, diverges
31,968,3002,952,400triples, diverges

Moving the ratio from 1.1 to 1.5 barely changes the second or third term, yet the 10th term grows sixteen-fold. That is the defining feature of geometric growth: small differences in the ratio compound into enormous differences later.

Infinite sums when |r| is below 1

The infinite geometric series is the one piece of this topic that surprises people: an endless list of positive numbers can still add up to a finite total. The condition is simply that the terms shrink fast enough, which happens exactly when the absolute value of r is under 1. The table starts every series at a₁ = 100 and compares the true limit against the sum of the first ten terms.

Ratio r Infinite sum S∞ Sum of first 10 terms Still missing
0.1111.111111111.1111110.000000
0.25133.333333133.3332060.000127
0.5200199.8046880.195313
2/3300294.7975415.202459
0.75400377.47459422.525406
0.91,000651.32156348.67844
−0.566.66666766.6015630.065104

The classic textbook use is turning a repeating decimal into a fraction. Write 0.333 repeating as 0.3 + 0.03 + 0.003 and you have a₁ = 0.3 with r = 0.1, so the sum is 0.3 / 0.9 = 1/3. The same argument on 0.9 + 0.09 + 0.009 gives 0.9 / 0.9 = 1, which is the honest proof that 0.999 repeating equals exactly one.

How to use this geometric sequence calculator

  1. Pick your mode. Use "I know a₁ and r" when the problem hands you the first term and the ratio. Use "I know two terms" when it only gives you two scattered terms.
  2. Enter the first term a₁. It can be negative or a decimal, but never zero.
  3. Enter the common ratio r. Divide any term by the one before it to find it. Negative ratios and fractions are fine.
  4. Enter n, the position of the term you want. Whole numbers from 1 to 10,000.
  5. Read the result. The headline shows aₙ. The tiles below give the partial sum, the infinite sum (or "diverges"), the first term and the percentage change per step.
  6. Scroll for the working. The rule card shows the explicit and recursive formulas, the table lists the first 25 terms with a running sum, and the step-by-step panel walks through the algebra.

Who this calculator is for

  • Algebra 2 and precalculus students checking nth term and series homework before it is due.
  • SAT, ACT and AP Calculus test takers practicing convergence questions where the |r| < 1 condition is the whole point.
  • Teachers and tutors generating clean example sequences with known sums.
  • Finance and science users modeling anything that changes by a fixed percentage per period, from compounding balances to radioactive decay.
  • Programmers sizing exponential backoff delays, buffer-doubling strategies or binary tree node counts.

Key terms explained

  • First term (a₁): the value the sequence starts at. It scales everything, since every later term is a multiple of it.
  • Common ratio (r): the fixed multiplier between consecutive terms, found by dividing any term by the one before it.
  • Explicit formula: aₙ = a₁rⁿ⁻¹, which jumps straight to any term.
  • Recursive formula: aₙ = aₙ₋₁ × r, which describes each step but forces you to walk the list.
  • Partial sum (Sₙ): the total of the first n terms, always counted from term 1.
  • Convergence: the property that the partial sums approach a fixed limit, which for a geometric series happens exactly when |r| < 1.
  • Geometric mean: the middle term of any three consecutive terms equals the square root of the product of its neighboring terms. For 3, 6, 12 that is the square root of 36, which is 6.

Geometric versus arithmetic growth side by side

Both sequences below start at 100 and run for 10 terms. The arithmetic one adds 10 per step; the geometric one multiplies by 1.10 per step. They look almost identical at first and separate sharply later.

Measure Arithmetic (d = 10) Geometric (r = 1.10)
2nd term110110
5th term140146.41
10th term190235.79
Sum of 10 terms1,4501,593.74

Both start at the same place and even share the same second term, yet the geometric total is 143.74 higher after only ten steps. Stretch the same comparison to 30 steps and the geometric version is many times larger. Compounding is the reason a fixed percentage return outruns a fixed dollar return over a long horizon, and the Compound Interest Calculator applies exactly this arithmetic to a balance.

What changes the result the most

  • The common ratio, by a wide margin. It sits in an exponent, so changing it from 1.05 to 1.10 multiplies the 20th term by about 2.42 rather than adding 5 percent.
  • The term position n. Each extra term multiplies the answer by r again, which is why long sequences explode or vanish.
  • The first term, which only scales the result. Doubling a₁ doubles every term and doubles both sums, never changing the shape.
  • Whether |r| crosses 1. This single threshold decides between a finite infinite sum and no sum at all, and it does so abruptly: r = 0.999 converges, r = 1.001 does not.
  • The sign of r. A negative ratio makes terms alternate, so the partial sums oscillate above and below the limit instead of rising to it.

Practical tips

  • To sum terms 11 through 20, compute S₂₀ and subtract S₁₀. For 3, 6, 12 that is 3,145,725 − 3,069 = 3,142,656.
  • To find which position holds a given value, use n = log(aₙ / a₁) / log(r) + 1. For a₁ = 3, r = 2 and aₙ = 3,072 that gives exactly 11.
  • Check any middle term against its neighboring terms: it should equal the square root of their product.
  • A ratio written as a percentage change converts easily. Growth of 5 percent per period means r = 1.05; a 15 percent yearly loss means r = 0.85.
  • If your ratio is negative, expect the running sum to bounce. With a₁ = 8 and r = −0.5 the sixth partial sum is 5.25 while the limit is 5.333333.

Real-world geometric sequences

Percentage change per period is the signature of a geometric sequence, and it appears everywhere. A vehicle that loses 15 percent of its value each year has r = 0.85, so a $30,000 car is worth $25,500 after one year, $21,675 after two, $18,423.75 after three and $13,311.16 after five. A drug with a four-hour half-life leaves 200 mg, 100 mg, 50 mg, 25 mg and 12.5 mg in the bloodstream at four-hour marks, a sequence with r = 0.5 that the Half-Life Calculator models directly. A ball dropped from 10 feet that rebounds to 60 percent of its previous height travels 10 + 2 × 10 × 0.6 / (1 − 0.6) = 40 feet in total before it stops, which is the infinite sum formula answering a physical question. And the famous grain-on-a-chessboard puzzle is nothing but a₁ = 1 with r = 2 and n = 64, whose sum is 2⁶⁴ − 1, or 18,446,744,073,709,551,615.

Limitations and assumptions

  • Results are shown as decimals rounded to 6 places, not exact fractions, so a ratio such as 1/3 displays as 0.333333.
  • Very large or very small values switch to scientific notation and carry ordinary floating-point rounding beyond about 15 significant digits.
  • The ratio must be a real number. Complex ratios and sequences whose ratio changes from step to step are outside the scope.
  • The two-term mode returns the principal real root. When the position gap is even and both values are positive, a negative ratio of the same magnitude also fits, so check the sign of your other terms.
  • The tool assumes your list really is geometric; it cannot tell you that your data merely looks exponential.

Which calculator should you use?

This page answers "what is the nth term and the sum of a sequence that multiplies?" A sister tool fits better for neighboring questions. Use the Arithmetic Sequence Calculator when the gap between terms is constant rather than the ratio. Use the Compound Interest Calculator when the sequence is a money balance and you want dollars, deposits and years instead of a₁, r and n. Use the Exponent Calculator when you only need to evaluate a single power such as 2¹⁰. Use the Half-Life Calculator for decay stated in half-lives rather than a ratio. Use the Fibonacci Calculator when each term is the sum of the two before it, which is neither arithmetic nor geometric.

โš ๏ธ Common mistakes & edge cases

Using rⁿ instead of rⁿ⁻¹

The first term needs zero multiplications, so the exponent is one less than the position. Writing 3 × 2¹⁰ gives 3,072 instead of the correct 1,536: every answer comes out exactly one factor of r too large.

Claiming an infinite sum when |r| is 1 or more

S∞ = a₁ / (1 − r) only exists when the absolute value of r is under 1. Feeding r = 2 into it returns −a₁, a meaningless negative number for a series of growing positive terms. Check the condition before you apply the formula.

Adding the ratio instead of multiplying by it

A common ratio of 1.05 means multiply by 1.05, not add 1.05 or add 5. If your terms are 100, 105, 110, 115 the gap is constant, so the sequence is arithmetic and belongs in the arithmetic calculator instead.

Dividing by zero at r = 1

When every term is identical the partial sum formula breaks, because 1 − r is zero. The correct answer is Sₙ = n × a₁. Ten terms of 7 sum to 70, not to an error.

Forgetting the second root with an even position gap

If the 2nd term is 6 and the 4th term is 24, then r² = 4, so r can be 2 or −2. Both fit the two given terms but produce different third terms, 12 versus −12. Look at a third term to settle the sign.

Summing from the wrong starting point

Sₙ always counts from term 1. To add terms 5 through 10 of 3, 6, 12, compute S₁₀ − S₄ = 3,069 − 45 = 3,024. Mixing a shifted first term into the same formula double-counts.

Note: A ratio of exactly −1 is legal but never converges. The sequence flips between a₁ and −a₁ forever, and the partial sums alternate between a₁ and 0 without settling.

❓ Frequently asked questions

What is a geometric sequence?

A geometric sequence is a list of numbers in which every term is found by multiplying the term before it by the same fixed number. That fixed number is the common ratio, written r. In 3, 6, 12, 24, 48 the common ratio is 2, because each term is twice the one before. If the ratio between consecutive terms is not always the same, the sequence is not geometric.

What is the formula for the nth term of a geometric sequence?

The explicit formula is a_n = a_1 times r^(n-1), where a_1 is the first term, r is the common ratio and n is the position of the term you want. The exponent is n - 1, not n, because reaching the first term takes zero multiplications. For a_1 = 3 and r = 2, the 10th term is 3 times 2^9 = 3 times 512 = 1,536.

How do I find the sum of a geometric series?

Use S_n = a_1 times (1 - r^n) / (1 - r) for any ratio except r = 1. For the sequence starting 3, 6, 12 with 10 terms, S_10 = 3 times (1 - 1,024) / (1 - 2) = 3 times 1,023 = 3,069. When r = 1 every term is identical, so the formula would divide by zero and you simply use S_n = n times a_1 instead.

When does an infinite geometric series have a sum?

Only when the absolute value of the common ratio is less than 1. In that case the terms shrink toward zero fast enough for the total to settle at S = a_1 / (1 - r). Starting at 100 with r = 0.5 gives S = 100 / 0.5 = 200, and the first 10 terms already reach 199.804688. If the absolute value of r is 1 or larger, the series diverges and no finite sum exists.

How do I find the common ratio from two known terms?

Divide the two values and take the root of the position gap: r = (a_k / a_m)^(1/(k - m)). If the 3rd term is 20 and the 7th term is 320, then r = (320 / 20)^(1/4) = 16^(0.25) = 2. Back up to the first term with a_1 = a_m / r^(m-1), which here gives 20 / 4 = 5. The two-term mode of this calculator does both steps for you.

Can the common ratio be negative or a fraction?

Yes. A negative ratio makes the sequence alternate in sign: 8, -4, 2, -1 has r = -0.5. A fractional ratio between -1 and 1 makes the terms shrink, which is exactly the case where an infinite sum exists. The formulas never change. A ratio of exactly 1 gives a constant sequence, and a ratio of exactly -1 flips between two values forever and never converges.

What is the difference between an arithmetic and a geometric sequence?

An arithmetic sequence adds a constant amount each step, so it plots as a straight line. A geometric sequence multiplies by a constant ratio each step, so it curves. Starting at 100, adding 10 per step reaches 190 at the 10th term and totals 1,450, while multiplying by 1.10 per step reaches about 235.79 and totals about 1,593.74. Arithmetic growth is linear; geometric growth compounds.

How do I find which term a given value is?

Rearrange the nth term formula with logarithms: n = log(a_n / a_1) / log(r) + 1. For the sequence starting at 3 with r = 2, the value 3,072 sits at n = log(1,024) / log(2) + 1 = 10 + 1 = 11. If the result is not a whole number, that value never appears in the sequence. This trick only works when r is positive, since logarithms of negative numbers are undefined in the real numbers.

Is a geometric sequence the same as a geometric series?

No, though the two words are used loosely. The sequence is the list of terms itself, such as 3, 6, 12, 24. The series is what you get when you add them, such as 3 + 6 + 12 + 24 = 45. The nth term formula belongs to the sequence and the sum formula S_n belongs to the series. This page reports both, which is why it doubles as a geometric series calculator.

What is a geometric progression?

Geometric progression is another name for a geometric sequence, used more often in British and Indian textbooks. It means exactly the same thing: a list in which each term is the previous one multiplied by a fixed ratio. A geometric progression calculator, a geometric sequence calculator and a geometric series calculator all apply the same two identities, a_n = a_1 r^(n-1) and S_n = a_1 (1 - r^n) / (1 - r).

Why does 0.999 repeating equal exactly 1?

Write it as a geometric series: 0.9 + 0.09 + 0.009 + ... has a_1 = 0.9 and r = 0.1. Since the absolute value of r is below 1, the infinite sum is 0.9 / (1 - 0.1) = 0.9 / 0.9 = 1 exactly. The same method turns any repeating decimal into a fraction: 0.333 repeating is 0.3 / 0.9 = 1/3. This is a standard application of the infinite geometric series formula, not a rounding trick.

Can the first term of a geometric sequence be zero?

No. If a_1 were 0, every later term would also be 0 and the common ratio would be undefined, since you cannot divide by zero to recover it. For the same reason no term anywhere in a genuine geometric sequence can be zero. This calculator rejects a first term of 0 and rejects a known term of 0 in the two-term mode.

How large a term position can this calculator handle?

You can request any whole-number position up to 10,000, and the nth term and the sum come straight from the closed-form formulas rather than a loop, so the answer is instant. Geometric growth is explosive, though: with r = 2 the 60th term already exceeds 10^17, so results beyond about 15 digits switch to scientific notation and carry the usual floating-point rounding.

Where do geometric sequences show up in real life?

Anywhere something changes by a fixed percentage per period: compound interest at a fixed rate, population growth, radioactive decay and drug half-lives, straight percentage depreciation of a vehicle, the rebound height of a bouncing ball and the pixel steps of a zoom control. A quantity that changes by a fixed amount instead of a fixed percentage is arithmetic, not geometric.

Is this geometric sequence calculator free?

Yes. There is no sign-up, no fee and no limit on how many sequences you can run. Enter a first term and ratio, or two known terms, as many times as you like. Every result is computed in your browser from the exact closed-form identities, so nothing you type is sent anywhere.

๐Ÿ’ก Good to know

The doubling penny beats the million dollars

A penny that doubles daily for 30 days is a geometric sequence with a₁ = $0.01 and r = 2. On day 30 alone it pays $5,368,709.12, and the 30 days together total $10,737,418.23. That is the clearest illustration of why geometric growth outruns anything linear given enough steps.

A ratio near 1 converges painfully slowly

With a₁ = 100 and r = 0.9 the infinite sum is 1,000, but ten terms only reach 651.32156 and you need 44 terms to get within 1 percent of the limit. Compare that with r = 0.1, where ten terms already match the limit to six decimals.

Take logarithms and geometric becomes arithmetic

The logarithms of a geometric sequence form an arithmetic sequence, because log(a₁rⁿ⁻¹) = log a₁ + (n − 1) log r. That is why exponential data plots as a straight line on a log scale, and it is a fast way to test whether a data set is geometric at all.

๐Ÿ“š Sources & method

Everything on this page is deterministic mathematics that needs no external source. The nth term identity aₙ = a₁rⁿ⁻¹, the partial sum identity Sₙ = a₁(1 − rⁿ)/(1 − r) and the infinite sum identity S∞ = a₁/(1 − r) for |r| < 1 are exact algebraic consequences of the definition that consecutive terms share a constant ratio. The partial sum follows in two lines from the telescoping trick Sₙ − rSₙ = a₁ − a₁rⁿ, and the infinite sum is its limit as rⁿ approaches zero.

The derived relations used here come from the same identities: r = (aₖ/aₘ)1/(k − m), a₁ = aₘ / rm − 1, n = log(aₙ/a₁) / log(r) + 1, and the constant case Sₙ = n × a₁ when r = 1. The arithmetic comparison uses the standard identities aₙ = a₁ + (n − 1)d and Sₙ = n/2 · (a₁ + aₙ), which are equally exact.

Every worked example, table value and figure above was computed directly from those formulas and cross-checked two ways, once with the closed form and once by multiplying and adding the terms one at a time. No legal, tax, financial or health figures appear on this page, so no agency data is cited. The dollar amounts in the depreciation, penny-doubling and bouncing-ball examples are illustrative inputs chosen to demonstrate the formulas, not market rates or published statistics.

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