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Ohm's Law Calculator

Solve volts, amps, ohms & watts from any two values

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Last updated October 2026

Method: Standard Ohm's law (V = I × R) combined with the power equation (P = V × I, P = I² × R, P = V² ÷ R). From any two of the four quantities, the other two are solved algebraically.

Included: Voltage, current, resistance and power, plus the exact formula used to derive each unknown value.

Not included: AC impedance and power factor, temperature drift, wire and connector resistance, component tolerances, and code-based wire or fuse sizing. Results are ideal estimates, not an engineering sign-off.

⚡ Enter any two values

Select the two quantities you know, type their values, and we'll solve the other two.

🔌 Power dissipated

60W
Voltage (V)
120 V
Current (I)
0.5 A
Resistance (R)
240 Ω

📐 Formulas used

Solved forFormula
Current (I)I = V ÷ R
Power (P)P = V² ÷ R

All four quantities are tied together by Ohm's law (V = I × R) and the power equation (P = V × I). From any two, the remaining two are fully determined.

⚠️ Estimate only. These are ideal DC values for a purely resistive load. Real circuits vary with temperature, wire resistance and AC power factor. Size wires and breakers by the National Electrical Code (for example, 125% of a continuous load on a branch circuit), and pick resistors rated well above the power shown.

Ohm's law calculator: everything you need to know

An Ohm's law calculator solves any two of voltage, current, resistance and power for the missing two using V = I × R and P = V × I. Enter 120 V across 240 Ω, for example, and it returns 0.5 A of current and 60 W of power instantly: the numbers behind an ordinary 60-watt incandescent bulb on a wall outlet.

This tool covers the electrical values inside a single load. If you already know the current and want to know how much voltage a long cable run loses on the way to that load, switch to the Voltage Drop Calculator, which factors in wire gauge, length and material. Use Ohm's law here to solve the circuit, then voltage drop to size the feed to it.

A worked example with real numbers

Suppose you know two things about a circuit: the supply is 120 V and the load is 240 Ω. Tick "Voltage" and "Resistance," enter those values, and the calculator works as follows:

  • Current: I = V ÷ R = 120 ÷ 240 = 0.5 A
  • Power: P = V² ÷ R = (120 × 120) ÷ 240 = 14,400 ÷ 240 = 60 W

So the full picture is 120 V, 0.5 A, 240 Ω and 60 W, exactly the 60-watt bulb from the intro. Start from a different pair and you get the same answer: if you instead knew the bulb is 60 W at 120 V, the calculator would give I = P ÷ V = 0.5 A and R = V² ÷ P = 240 Ω. Any two knowns lock in the whole circuit.

Solved Ohm's law problems (step by step)

These are the exact textbook-style questions people search for, worked out with the formula the calculator applies. Every result is computed; pick the row that matches your two known values.

You know Find Formula Answer
360 Ω at 120 VCurrentI = V ÷ R = 120 ÷ 3600.33 A
12 A at 120 VResistanceR = V ÷ I = 120 ÷ 1210 Ω
20 A through 12 ΩVoltageV = I × R = 20 × 12240 V
0.15 A through 4,200 ΩPowerP = I² × R = 0.15² × 420094.5 W
0.5 A at 120 VPowerP = V × I = 120 × 0.560 W
0.02 A at 120 VPowerP = V × I = 120 × 0.022.4 W

The formulas

Four equations connect the four quantities. The calculator picks whichever ones fit the pair you entered:

V = I × R P = V × I P = I² × R P = V² ÷ R

Here V is voltage in volts, I is current in amps, R is resistance in ohms (Ω), and P is power in watts. Every other form (I = V ÷ R, R = V ÷ I, V = √(P × R) and so on) is just algebra on these four. That is why you only ever need two values to start.

Current and power for common voltages and resistances

Look up a resistance down the left and a supply voltage across the top; each cell shows the resulting current and power (P = V² ÷ R) for an ideal resistive load. The 5 V and 12 V columns cover electronics and automotive work; 120 V and 240 V are US household supplies.

Resistance 5 V 12 V 120 V 240 V
10 Ω0.5 A / 2.5 W1.2 A / 14.4 W12 A / 1,440 W24 A / 5,760 W
50 Ω0.1 A / 0.5 W0.24 A / 2.88 W2.4 A / 288 W4.8 A / 1,152 W
100 Ω0.05 A / 0.25 W0.12 A / 1.44 W1.2 A / 144 W2.4 A / 576 W
240 Ω0.021 A / 0.104 W0.05 A / 0.6 W0.5 A / 60 W1 A / 240 W
360 Ω0.014 A / 0.069 W0.033 A / 0.4 W0.33 A / 40 W0.67 A / 160 W
1,000 Ω0.005 A / 0.025 W0.012 A / 0.144 W0.12 A / 14.4 W0.24 A / 57.6 W
4,200 Ω0.0012 A / 0.006 W0.0029 A / 0.034 W0.029 A / 3.43 W0.057 A / 13.7 W

Ohms to watts conversion

Ohms alone don't convert to watts: you also need a voltage (or current), because power depends on both. Assuming the whole voltage sits across the resistor, this table gives the current and power at 120 V and at 12 V using P = V² ÷ R.

Resistance At 120 V At 12 V
1 Ω120 A / 14,400 W12 A / 144 W
2 Ω60 A / 7,200 W6 A / 72 W
5 Ω24 A / 2,880 W2.4 A / 28.8 W
10 Ω12 A / 1,440 W1.2 A / 14.4 W
50 Ω2.4 A / 288 W0.24 A / 2.88 W
100 Ω1.2 A / 144 W0.12 A / 1.44 W
240 Ω0.5 A / 60 W0.05 A / 0.6 W
1,000 Ω0.12 A / 14.4 W0.012 A / 0.144 W

The 120 V rows on the left make clear why a low-ohm load is dangerous on mains: a 1 Ω or 2 Ω short across a 120 V outlet tries to pass tens of amps and thousands of watts, which is exactly what a fuse or breaker is there to interrupt.

How to measure your two known values

If you are working on a real circuit rather than a textbook problem, here is how to get the two inputs you need with a multimeter:

  1. Voltage: set the meter to DC (or AC) volts and place the probes across the component or supply, in parallel, without breaking the circuit.
  2. Current: set the meter to amps, then break the circuit and put the meter in series so all the current flows through it. Mind the meter's current limit and fuse.
  3. Resistance: power off and isolate the component, then set the meter to ohms and measure across it. Measuring resistance in a live circuit gives wrong readings.
  4. Power: you rarely measure watts directly on a small project; instead measure two of the others and let the calculator derive it.

Pick whichever two are easiest and safest to obtain, enter them, and the tool fills in the rest.

Who this calculator is for

  • Students and hobbyists checking homework or breadboard projects without rearranging the formula by hand.
  • Makers and electronics tinkerers sizing current-limiting resistors for LEDs and picking the right wattage part.
  • DIY homeowners sanity-checking whether a device's draw fits a circuit, an extension cord, or a power supply.
  • Technicians and apprentices who want a quick, reliable second opinion in the field.
  • Anyone curious who sees "120V," "15A," or "1500W" on a label and wants to know what the other numbers are.

Key terms explained

  • Voltage (V, volts): the electrical "pressure" or potential difference that pushes current through a circuit.
  • Current (I, amps): the rate of flow of electric charge. More current means more heat in the wires and components.
  • Resistance (R, ohms / Ω): how strongly a component opposes current. A higher resistance means less current for the same voltage.
  • Power (P, watts): the rate at which the circuit converts electrical energy to heat, light, or motion.
  • Impedance (Z): the AC equivalent of resistance, which also accounts for capacitors and inductors. Swap R for Z in AC circuits.
  • Power factor: in AC circuits, the fraction of apparent power that does real work. A purely resistive load has a power factor of 1.
  • Energy (Wh / kWh): power multiplied by time. This is what your utility bills you for.

Three quick scenarios

1. Sizing an LED resistor. A 5 mm LED wants about 20 mA (0.02 A) and drops roughly 2 V; your supply is 5 V. The resistor must drop the remaining 3 V, so R = V ÷ I = 3 ÷ 0.02 = 150 Ω, dissipating P = I² × R = 0.02² × 150 = 0.06 W. A common ¼-watt resistor has plenty of headroom.

2. Checking a space heater on a circuit. A heater rated 1,500 W on 120 V draws I = P ÷ V = 1,500 ÷ 120 = 12.5 A. That is most of a 15 A branch circuit, so you should not run much else on it, and never on a thin extension cord.

3. Finding an unknown resistance. You measure 9 V across a component and 0.03 A through it. R = V ÷ I = 9 ÷ 0.03 = 300 Ω, using P = V × I = 0.27 W of power.

Series and parallel resistors

Real circuits rarely have a single resistor, so before you reach for Ohm's law you often need to combine several into one equivalent resistance, then enter that value here. The rules are short:

  • In series (resistors end-to-end, one current path), resistances simply add: R = R₁ + R₂ + R₃ … The same current flows through every part, and the voltage divides between them in proportion to each resistance.
  • In parallel (resistors side by side, multiple current paths), the reciprocals add: 1 ÷ R = 1 ÷ R₁ + 1 ÷ R₂ + … The total is always smaller than the smallest individual resistor, and each branch sees the full supply voltage.

For example, two 100 Ω resistors in series make 200 Ω, but the same two in parallel make just 50 Ω. A handy shortcut for exactly two resistors in parallel is R = (R₁ × R₂) ÷ (R₁ + R₂). Once you have the single equivalent resistance, type it into the calculator with your supply voltage and it returns the total current and power the network draws. Then work back to each branch: in parallel, find each branch current with I = V ÷ R using that branch's resistance; in series, find each resistor's voltage with V = I × R using the shared current.

From power to energy and electricity cost

Ohm's law and the power equation give you watts, the instantaneous rate of energy use, but your electricity bill is in kilowatt-hours (kWh), which is power multiplied by time. To turn a calculated wattage into a running cost, use two more steps:

Energy (kWh) = Watts ÷ 1000 × Hours Cost = Energy (kWh) × Rate per kWh

Suppose the calculator tells you a heater draws 1,500 W. Run it 5 hours a day and that is 1,500 ÷ 1000 × 5 = 7.5 kWh per day. At the U.S. average residential price of 18.31 cents per kWh (EIA, July 2026), that is about $1.37 a day, or close to $41 a month. The same chain works for any device: solve its power here from any two known values, multiply by the hours you actually use it, then multiply by your local rate (printed on your utility bill). Energy, not power alone, drives the bill: a 10 W LED left on for 5 hours uses 0.05 kWh, while a 1,500 W hair dryer used for 10 minutes uses 0.25 kWh, five times as much.

What changes the result the most

  • Resistance: for a fixed voltage, current and power scale inversely with resistance: halving R doubles both.
  • Voltage: power rises with the square of voltage (P = V² ÷ R), so even a small voltage increase sharply raises heat.
  • Unit prefixes: entering 2.2 kΩ as "2.2" instead of "2200," or 20 mA as "20" instead of "0.02," throws the answer off by orders of magnitude.
  • AC vs. DC: reactive loads (motors, transformers) need impedance and power factor; treating them as purely resistive overstates real power.

Practical tips

  • Convert prefixes first: work in plain volts, amps, ohms and watts. 500 mA = 0.5 A; 4.7 kΩ = 4,700 Ω; 2 MΩ = 2,000,000 Ω.
  • Leave margin: pick resistors rated well above their calculated dissipation (about twice is a common design practice), and size wires and breakers by the NEC, which uses 125% of a continuous load for branch circuits.
  • Round to real parts: if the math says 147 Ω, you will buy the nearest standard value (150 Ω), so recheck the current and power at that value.
  • Mind the heat: watts become heat. A part dissipating near its rating gets hot; give it air or pick a bigger one.

Limitations and assumptions

This calculator models an ideal DC circuit with a single, constant, purely resistive load. Keep these caveats in mind:

  • It ignores temperature effects: real resistance changes as components warm up.
  • It ignores wire, contact and source resistance, which subtract a little voltage in real circuits.
  • For AC with reactance (motors, capacitors, inductors), substitute impedance for resistance and apply the power factor.
  • It does not size wires, breakers or fuses; that follows electrical code and ampacity tables, not Ohm's law alone.
  • Component tolerances (often ±5%) mean the real value drifts slightly from the calculated one.

Related calculators

Ohm's law answers "what are the other electrical values?" Once you know the current, the next question is usually how much voltage you lose over a long cable run, which the Voltage Drop Calculator handles with wire gauge, length and material against the 3% NEC recommendation. The Wire Size Calculator picks a conductor for a load and run length, and the Watts to Amps Calculator converts appliance ratings for AC and DC circuits. For networks of resistors, combine them first with the Parallel Resistor Calculator, split a voltage with the Voltage Divider Calculator, and read a part's value from its bands with the Resistor Color Code Calculator. To price the energy a load uses, finish with the Electricity Cost Calculator.

Sources

Ohm's law and the power equation themselves are exact definitions for an ideal resistive load, so every number above can be reproduced by hand.

⚠️ Common mistakes & edge cases

Mixing up unit prefixes

Entering 2.2 kΩ as "2.2" or 20 mA as "20" is the number-one error. Convert everything to plain volts, amps, ohms and watts first: 2.2 kΩ = 2,200 Ω, 20 mA = 0.02 A.

Treating an AC motor like a resistor

Inductive and capacitive loads have impedance, not just resistance, and a power factor below 1. Using plain Ohm's law on them overstates the real power: swap R for impedance Z and multiply power by the power factor.

Forgetting the resistor's power rating

The calculator gives the resistance you need, but a resistor also has a wattage limit. Always check P = I² × R and pick a part rated well above it, or it will overheat and fail.

Using ideal values to size wire or fuses

Ohm's law gives the current, but safe wire and fuse sizing follows the NEC and depends on insulation, length and ambient temperature. A continuous load needs conductors and a breaker rated for at least 125% of its current, and the wire comes from an ampacity table, not the bare calculated amps.

Note: This calculator gives an estimate for an ideal DC, resistive circuit. For real installations, account for AC power factor, temperature and code requirements, and consult a licensed electrician for anything safety-critical.

❓ Frequently asked questions

What is Ohm's law?

Ohm's law states that the current through a conductor is directly proportional to the voltage across it and inversely proportional to its resistance: V = I × R. In words, voltage (volts) equals current (amps) times resistance (ohms). Rearranged, I = V ÷ R and R = V ÷ I. It is the single most important relationship in basic electronics and electrical work.

How do I use this Ohm's law calculator?

Tick the two quantities you already know (any two of voltage, current, resistance or power) and type their values. The other two appear instantly as you type: the tool applies Ohm's law and the power equation and shows exactly which formula it used for each one.

What is the formula linking voltage, current, resistance and power?

Four formulas tie them together: V = I × R (Ohm's law), P = V × I (power), P = I² × R, and P = V² ÷ R. Because any two of the four quantities fully determine the other two, you can start from whichever pair you happen to know.

How do I calculate watts from volts and amps?

Power in watts equals voltage times current: P = V × I. For example, a device drawing 0.5 A at 120 V uses 120 × 0.5 = 60 watts. If you know resistance instead of one of those, use P = V² ÷ R or P = I² × R.

How do I find resistance from voltage and current?

Divide voltage by current: R = V ÷ I. A 12 V supply pushing 2 A through a load means the load resistance is 12 ÷ 2 = 6 ohms. This is the most direct rearrangement of Ohm's law.

Does Ohm's law work for AC circuits?

Ohm's law applies cleanly to DC and to purely resistive AC loads. For AC circuits with inductors or capacitors you replace resistance (R) with impedance (Z), and real power must account for the power factor: P = V × I × power factor. This calculator assumes ideal DC or a resistive load, so use it as a close estimate for AC and refine with impedance and power factor where needed.

What units does the calculator use?

Volts (V) for voltage, amps (A) for current, ohms (Ω) for resistance and watts (W) for power. If your values are in milliamps or kilo-ohms, convert first: 500 mA = 0.5 A, and 2.2 kΩ = 2,200 Ω. Mixing prefixes is the most common source of wrong answers.

How do I choose a resistor and check its power rating?

Use Ohm's law to find the resistance you need (R = V ÷ I), then use P = I² × R to find how much power the resistor must dissipate. Pick a resistor whose wattage rating comfortably exceeds that figure; a common design practice is a part rated for about twice the calculated power, so it runs cool and lasts.

Why is my real-world measurement different from the calculated value?

Calculated values assume ideal conditions: a perfect resistor, no wire resistance, a fixed supply voltage and a stable temperature. In practice, resistance drifts with temperature, wires and connectors add a little resistance, supplies sag under load, and component tolerances (often ±5%) shift the numbers. Treat the result as a precise starting point and size components with margin.

Can I use Ohm's law to size wire or a fuse?

Ohm's law gives you the current, which is the starting point, but wire and fuse sizing follows code (the NEC in the US) and depends on conductor type, insulation, length, and ambient temperature, not just the current. Calculate the current here, then apply the code rules: for example, the NEC sizes branch-circuit conductors and breakers at no less than 125% of a continuous load (one that runs for 3 hours or more), and the wire then comes from the ampacity table. A licensed electrician should confirm the final size.

What is the difference between power and energy?

Power (watts) is the instantaneous rate of energy use; energy (watt-hours or kilowatt-hours) is power multiplied by time. A 60 W bulb left on for 10 hours uses 60 × 10 = 600 watt-hours, or 0.6 kWh. This calculator gives you power; multiply by run time to estimate energy and electricity cost.

How do I use Ohm's law with resistors in series or parallel?

First combine the resistors into one equivalent value, then enter that. In series, resistances add: R = R1 + R2 + R3. In parallel, the reciprocals add: 1 ÷ R = 1 ÷ R1 + 1 ÷ R2, so the total is smaller than the smallest resistor (for just two, R = R1 × R2 ÷ (R1 + R2)). Type the equivalent resistance with your supply voltage to get the total current and power, then work back to each branch with Ohm's law.

How do I turn watts into electricity cost?

Convert power to energy, then multiply by your rate. Energy in kilowatt-hours = watts ÷ 1000 × hours used, and cost = kWh × your rate per kWh. For example, a 1,500 W heater run 5 hours a day uses 7.5 kWh; at the U.S. average residential price of 18.31 cents per kWh (EIA, July 2026) that is about $1.37 a day. Solve the wattage here from any two values, then multiply by your run time and local rate.

What is the current in a 360-ohm bulb at 120 volts?

Use I = V ÷ R. A 360 Ω bulb on a 120 V supply draws I = 120 ÷ 360 = 0.33 A, and dissipates P = V² ÷ R = 14,400 ÷ 360 = 40 W. The same rearrangement gives the current for any resistor: divide the voltage across it by its resistance in ohms.

How do I convert ohms to watts?

Ohms alone don't give watts, because power also depends on the voltage or current, so you need one of those too. With a known voltage, use P = V² ÷ R; with a known current, use P = I² × R. For example, a 10 Ω load across 120 V dissipates 120² ÷ 10 = 1,440 W, while the same 10 Ω carrying 2 A dissipates 2² × 10 = 40 W.

Is this Ohm's law calculator free?

Yes. It runs entirely in your browser, needs no sign-up, and works on phone, tablet or desktop. Nothing you type is sent anywhere; the math happens locally on your device.

💡 Good to know

Any two values reveal the whole circuit

Voltage, current, resistance and power are locked together by V = I × R and P = V × I. Know any two and the other two are fixed; there is no second possible answer.

Power rises with the square of voltage

Because P = V² ÷ R, doubling the voltage on the same resistance quadruples the power, and the heat. That is why even small voltage changes matter so much for component ratings.

Estimate, then add margin

The numbers here assume an ideal circuit. Pick resistors rated well above the calculated power, and size wires and breakers by the code (125% of a continuous load) so nothing runs at its absolute limit.

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